装配件应力分析？

穆穆

图示两个零件螺纹连接，受轴向拉应力，我要用cosmos校核螺纹的强度，应该使用什么配合关系装配起来？哪位大侠帮忙？
<img src="attachments/dvbbs/2004-2/200422016301156690.jpg" border="0" onload="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.alt=\'Click here to open new window\nCTRL+Mouse wheel to zoom in/out\';}" onmouseover="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.style.cursor=\'hand\'; this.alt=\'Click here to open new window\nCTRL+Mouse wheel to zoom in/out\';}" onclick="if(!this.resized) {return true;} else {window.open(\'attachments/dvbbs/2004-2/200422016301156690.jpg\');}" onmousewheel="return imgzoom(this);" alt="" />

cefrykl

传part上来。

smltiger

依此圖分析 有
1.同心圓
2.面面或基準面對基準面重合
P.S 如果要避免牙干涉調整螺旋線起點角度值
     從透視圖面觀看組合情形
還有疑問 Part丟上來 等你哦！

穆穆

smltiger

以下是引用穆穆在2004-2-21 8:20:22的发言：
零件和装配件，怎么装配？

三兩下[em14][em14]
干涉證明
<img src="attachments/dvbbs/2004-2/200422111164710407.jpg" border="0" onload="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.alt=\'Click here to open new window\nCTRL+Mouse wheel to zoom in/out\';}" onmouseover="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.style.cursor=\'hand\'; this.alt=\'Click here to open new window\nCTRL+Mouse wheel to zoom in/out\';}" onclick="if(!this.resized) {return true;} else {window.open(\'attachments/dvbbs/2004-2/200422111164710407.jpg\');}" onmousewheel="return imgzoom(this);" alt="" />

smltiger

看看組合件

穆穆