第一题难就难在要在一个模拟的过程中实现多次的往复。我是按照cefrykl大大在教学的帖子中利用“它人之力“来驱动的,即多加一个零件,再隐藏。
锥齿轮传动一题我先选择两个齿轮的两点,设置平行距离,用菜单栏工具下的干涉检查,如果有干涉,则调整平行距离,直到出现干涉为零,然后保持这个状态,删除这个平行距离的配合。这样起始位置就能保持不干涉了,这个方法我觉得也不是很好,相当于手动调整了,不知您是如何解决的。
<img src="attachments/dvbbs/2004-5/200451017281767562.jpg" border="0" onload="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.alt=\'Click here to open new window\nCTRL+Mouse wheel to zoom in/out\';}" onmouseover="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.style.cursor=\'hand\'; this.alt=\'Click here to open new window\nCTRL+Mouse wheel to zoom in/out\';}" onclick="if(!this.resized) {return true;} else {window.open(\'attachments/dvbbs/2004-5/200451017281767562.jpg\');}" onmousewheel="return imgzoom(this);" alt="" />
这是爬楼梯的特征树,这题应该有多种配合方式,不同的搭配能找出多种方法
<img src="attachments/dvbbs/2004-5/200451017291532911.jpg" border="0" onload="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.alt=\'Click here to open new window\nCTRL+Mouse wheel to zoom in/out\';}" onmouseover="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.style.cursor=\'hand\'; this.alt=\'Click here to open new window\nCTRL+Mouse wheel to zoom in/out\';}" onclick="if(!this.resized) {return true;} else {window.open(\'attachments/dvbbs/2004-5/200451017291532911.jpg\');}" onmousewheel="return imgzoom(this);" alt="" />
最后一题有难度,想了很久没想出来,版大能否提供一点思路,谢谢[em57][em57][em57]
[此贴子已经被作者于2004-5-10 17:33:14编辑过]
|